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Proof step 15 from proof wand-right (
previous step
)
P(H1), Q0(H0), H1 ⊥ H0, ∀ H. P(H) → ((Q0 -* Q1))(H) ⊦ Q1(H1 ∪ H0)
User applied rule all left
And obtained the following new goals
Proof step 16
:
P(H1), Q0(H0), H1 ⊥ H0, P(H1) → ((Q0 -* Q1))(H1) ⊦ Q1(H1 ∪ H0)
Rule argument
pos: left 4 terms: H1 abort: F discard: T computed: T
Additional information
Used terms: H1