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Proof step 43 from proof cf-map-unknown (previous step)

cf(r) = a × r0, r1 = r, rs1 ∩ rs0 = ∅, R[rs0, cf, af], ∀ r. r ∈ rs1 → af(r) = o, ∀ r2. (r2 ∈ rs1 ↔ r2 = r) ∧ (r2 ∈ rs1 → cf(r2) = (r2 = r ⊃ ce;(∅ ++ r)[r2])) ⊦ r = null, (o[r => a × r0] * R)[rs1 ∪ rs0, cf, af], r1 ∈ rs1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 44:
cf(r) = a × r0, rs1 ∩ rs0 = ∅, R[rs0, cf, af], ∀ r. r ∈ rs1 → af(r) = o, ∀ r1. (r1 ∈ rs1 ↔ r1 = r) ∧ (r1 ∈ rs1 → cf(r1) = (∅ ++ r)[r1]) ⊦ r = null, (o[r => a × r0] * R)[rs1 ∪ rs0, cf, af], r ∈ rs1

Proof step 43 from proof cf-map-unknown (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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