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Proof step 44 from proof cf-map-unknown (previous step)

cf(r) = a × r0, rs1 ∩ rs0 = ∅, R[rs0, cf, af], ∀ r. r ∈ rs1 → af(r) = o, ∀ r1. (r1 ∈ rs1 ↔ r1 = r) ∧ (r1 ∈ rs1 → cf(r1) = (∅ ++ r)[r1]) ⊦ r = null, (o[r => a × r0] * R)[rs1 ∪ rs0, cf, af], r ∈ rs1

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 5 terms: r

Additional information

Used terms: r