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Proof step 31 from proof aux-known (previous step)

rs1 ∩ rs0 = ∅, R[rs0, f, g], a0[r => o][rs1, f, g], a1[r => o][rs1, f, g(r; a1)], R[rs0, f, g(r; a1)] ⊦ true ∧ g(r) = a0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information