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Proof step 32 from proof aux-known (previous step)

rs1 ∩ rs0 = ∅, R[rs0, f, g(r; a1)], a1[r => o][rs1, f, g(r; a1)], a0[r => o][rs1, f, g], R[rs0, f, g] ⊦ g(r) = a0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 33:
⊦ R[rs, f, g] ↔ R(mk(rs, f, g))
Proof step 34:
rs1 ∩ rs0 = ∅, R[rs0, f, g], a0[r => o](mk(rs1, f, g)), a1[r => o][rs1, f, g(r; a1)], R[rs0, f, g(r; a1)] ⊦ g(r) = a0

Rule argument

spec: heap-fun, inst: heap-aux name: apply seq: ⊦ R[rs, f, g] ↔ R(mk(rs, f, g)) subst: [g, f, rs, R] → [g, f, rs1, a0[r => o]] flags: <all paths>

Additional information

Used terms: g, f, rs1, a0[r => o]