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Proof step 1 from proof embed-and (conclusion)

⊦ a[P0 ∧ P1] = (a[P0] ∧ a[P1])

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: heap-fun, inst: heap-aux name: mk-ext seq: ⊦ R0 = R1 ↔ (∀ rs, f, g. R0[rs, f, g] ↔ R1[rs, f, g]) subst: [R1, R0] → [a[P0] ∧ a[P1], a[P0 ∧ P1]] flags: <all paths>

Additional information

Used terms: a[P0] ∧ a[P1], a[P0 ∧ P1]