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Theorem embed-and

⊦ a[P0 ∧ P1] = (a[P0] ∧ a[P1])

Type: A user defined theorem
Validity: The proof is valid.
Features: s,
Comment:
Used by:
Used by units in proved state: linked-list-aux,
Proof exists?: Yes

View the proof

Infos about the proof

Proved?: Yes
Interactions: 6
Proof steps: 10
Used lemmas: lift-aux,
Used spec theorems:
- heap-fun/heap-aux/mk-ext
- heap-fun/heap-aux/apply
Used simplifier rules:
- heap-sep/heap-aux/and-com
- heap-sep/heap-aux/and-ass
- heap-sep/heap-aux/and
- heap-sep/and-com
- heap-sep/and-ass
- heap-sep/and