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Proof step 14 from proof embed-and (previous step)

⊦ P0(mk(rs, f)) ∧ P1(mk(rs, f)) ∧ (∀ r. r ∈ rs → g(r) = a) ↔ (P0(mk(rs, f)) ∧ (∀ r. r ∈ rs → g(r) = a)) ∧ a[P1](mk(rs, f, g))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information