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Proof step 1 from proof lift-ex-r (conclusion)

⊦ a[_∃ rP] = _∃(λ r. a[rP(r)])

User applied rule expand right

And obtained the following new goals

Proof step 2:
⊦ a[_∃ rP](Ha) ↔ (_∃(λ r. a[rP(r)]))(Ha)

Rule argument

pos: right 1

Additional information