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Proof step 2 from proof lift-ex-r (previous step)

⊦ a[_∃ rP](Ha) ↔ (_∃(λ r. a[rP(r)]))(Ha)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
⊦ a[_∃ rP](Ha) ↔ (∃ r. a[rP(r)](Ha))

Rule argument

Additional information

Used simplifier rules: ⊦ (_∃ rR)(Ha) ↔ (∃ r. rR(r)(Ha)); (s)