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Proof step 15 from proof modify-agree (previous step)

modify(rs)(H0, H), rtc(n0, modify(rs))(H, H1), ∀ rs, H0, H1. rtc(n0, modify(rs))(H0, H1) → ((H0 ≡ H1))(rs) ⊦ ((H0 ≡ H1))(rs)

User applied rule all left

And obtained the following new goals

Proof step 16:
modify(rs)(H0, H), rtc(n0, modify(rs))(H, H1), rtc(n0, modify(rs))(H, H1) → ((H ≡ H1))(rs) ⊦ ((H0 ≡ H1))(rs)

Rule argument

pos: left 3 terms: rs, H, H1 abort: F discard: T computed: T

Additional information

Used terms: rs, H, H1