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Proof step 16 from proof modify-agree (
previous step
)
modify(rs)(H0, H), rtc(n0, modify(rs))(H, H1), rtc(n0, modify(rs))(H, H1) → ((H ≡ H1))(rs) ⊦ ((H0 ≡ H1))(rs)
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 17
:
modify(rs)(H0, H), rtc(n0, modify(rs))(H, H1), ((H ≡ H1))(rs) ⊦ ((H0 ≡ H1))(rs)
Rule argument
Additional information