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Proof step 19 from proof wand-flatten (previous step)

P0(H2), P1(H1), H2 ⊥ H1, H ⊥ H2, H ⊥ H1, H2 ⊥ H, H1 ⊥ H2 ∧ H1 ⊥ H → P2(H1 ∪ H2 ∪ H) ⊦ P2((H2 ∪ H1) ∪ H)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 20:
P0(H2), P1(H1), P2(H1 ∪ H2 ∪ H), H ⊥ H1, H ⊥ H2, H2 ⊥ H1 ⊦ P2((H2 ∪ H1) ∪ H)

Rule argument

Additional information

Used simplifier rules: ⊦ H0 ⊥ H1 → H1 ⊥ H0; (s)