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Proof step 20 from proof wand-flatten (previous step)

P0(H2), P1(H1), P2(H1 ∪ H2 ∪ H), H ⊥ H1, H ⊥ H2, H2 ⊥ H1 ⊦ P2((H2 ∪ H1) ∪ H)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 21:
⊦ H0 ⊥ H1 → H1 ∪ H0 = H0 ∪ H1
Proof step 22:
P0(H2), P1(H1), P2(H1 ∪ H2 ∪ H), H2 ⊥ H1, H ⊥ H2, H ⊥ H1, H1 ⊥ H2 ⊦ P2((H1 ∪ H2) ∪ H)

Rule argument

spec: heap name: uni-com seq: ⊦ H0 ⊥ H1 → H1 ∪ H0 = H0 ∪ H1 subst: [H0, H1] → [H1, H2] flags: <all paths>

Additional information

Used simplifier rules: ⊦ H0 ⊥ H1 → H1 ⊥ H0; (s) Used terms: H1, H2