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Proof step 11 from proof wand-shift (previous step)

P0(H1), P1(H), H ⊥ H0, H ⊥ H1, H1 ⊥ H0, ∀ H1. H1 ⊥ H0 ∧ P1(H1) → P2(H1 ∪ H0) ⊦ ((P0 * P2))(H ∪ H1 ∪ H0)

User applied rule all left

And obtained the following new goals

Proof step 12:
P0(H1), P1(H), H1 ⊥ H0, H ⊥ H1, H ⊥ H0, H ⊥ H0 ∧ P1(H) → P2(H ∪ H0) ⊦ ((P0 * P2))(H ∪ H1 ∪ H0)

Rule argument

pos: left 6 terms: H abort: F discard: T computed: T

Additional information

Used terms: H