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Proof step 12 from proof wand-shift (
previous step
)
P0(H1), P1(H), H1 ⊥ H0, H ⊥ H1, H ⊥ H0, H ⊥ H0 ∧ P1(H) → P2(H ∪ H0) ⊦ ((P0 * P2))(H ∪ H1 ∪ H0)
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 13
:
P0(H1), P1(H), P2(H ∪ H0), H ⊥ H0, H ⊥ H1, H1 ⊥ H0 ⊦ ((P0 * P2))(H ∪ H1 ∪ H0)
Rule argument
Additional information