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Proof step 14 from proof subset-uni (
previous step
)
r ∈ H0, H0 ⊆ H1, H1 \ H0 ⊥ H0, r ∈ H1 ∨ r ∈ H0 ⊦ H0[r] = H1[r]
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 15
:
r ∈ H0, H0 ⊆ H1, H1 \ H0 ⊥ H0 ⊦ H0[r] = H1[r]
Rule argument
Additional information