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Proof step 15 from proof subset-uni (
previous step
)
r ∈ H0, H0 ⊆ H1, H1 \ H0 ⊥ H0 ⊦ H0[r] = H1[r]
User applied rule insert rewrite lemma
And obtained the following new goals
Proof step 16
:
⊦ H0 ⊆ H1 ∧ r ∈ H0 → H1[r] = H0[r]
Rule argument
spec: <toplevel> name: subset-at seq: ⊦ H0 ⊆ H1 ∧ r ∈ H0 → H1[r] = H0[r] subst: [H0, r, H1] → [H0, r, H1] flags: <all paths>
Additional information
Used terms: H0, r, H1