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Theorem uni-ass

⊦ H0 ⊥ H1 ∧ H1 ⊥ H ∧ H ⊥ H0 → (H0 ∪ H1) ∪ H = H0 ∪ H1 ∪ H

Type: A user defined theorem
Validity: The proof is valid.
Features:
Comment:
Used by:
Used by units in proved state: linked-list-aux, linked-list, heap-sep,
Proof exists?: Yes

View the proof

Infos about the proof

Proved?: Yes
Interactions: 5
Proof steps: 13
Used lemmas: disj-r, at-uni, disj-distr-uni, disj-com-rw, disj-distr-uni-com, in-uni, ext,
Used spec theorems:
- Used simplifier rules: