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Proof step 4 from proof Sep-unfold (previous step)

m = n0 + m0, m0 < m, m0 ≤ m ⊦ nP ⊗_(n, m) = nP ⊗_(n, m0) * nP(n + m0) * nP ⊗_(n + m0 + 1, n0 - 1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
⊦ n0 = 0, nP ⊗_(n, n0 + m0) = nP ⊗_(n, m0) * nP(n + m0) * nP ⊗_(n + m0 + 1, n0 - 1)

Rule argument

Additional information

Used simplifier rules: c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ m < m + n ↔ n ≠ 0; (s)% ⊦ m < n → m ≤ n; (s)