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Proof step 5 from proof Sep-unfold (previous step)

⊦ n0 = 0, nP ⊗_(n, n0 + m0) = nP ⊗_(n, m0) * nP(n + m0) * nP ⊗_(n + m0 + 1, n0 - 1)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 6:
n0 = m + 1 ⊦ n0 = 0, nP ⊗_(n, n0 + m0) = nP ⊗_(n, m0) * nP(n + m0) * nP ⊗_(n + m0 + 1, m)

Rule argument

spec: nat name: elim-pred-c seq: n ≠ 0 ⊦ m = n - 1 ↔ n = m + 1 subst: [n, m] → [n0, m]

Additional information

Used simplifier rules: n ≠ 0 ⊦ m = n - 1 ↔ n = m + 1; (elim) Used terms: n0, m