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Proof step 1 from proof precise-ls (conclusion)

⊦ precise(ls(r, x))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ precise(P) ↔ (∀ H, H0, H1, H2. P(H) ∧ P(H0) ∧ H ⊥ H1 ∧ H0 ⊥ H2 ∧ H ∪ H1 = H0 ∪ H2 → H = H0)
Proof step 3:
⊦ ∀ H, H0, H1, H2. ls(r, x)(H) ∧ ls(r, x)(H0) ∧ H ⊥ H1 ∧ H0 ⊥ H2 ∧ H ∪ H1 = H0 ∪ H2 → H = H0

Rule argument

spec: heap-sep name: precise seq: ⊦ precise(P) ↔ (∀ H, H0, H1, H2. P(H) ∧ P(H0) ∧ H ⊥ H1 ∧ H0 ⊥ H2 ∧ H ∪ H1 = H0 ∪ H2 → H = H0) subst: [P] → [ls(r, x)] flags: <all paths>

Additional information

Used terms: ls(r, x)