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Proof step 3 from proof lls-one (previous step)

⊦ lls(r0, r1, a + []) = r0 => a × r1

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ a + x = a ' + x
Proof step 5:
⊦ lls(r0, r1, a ' + []) = r0 => a × r1

Rule argument

spec: list name: c seq: ⊦ a + x = a ' + x subst: [x, a] → [[], a] flags: <all paths>

Additional information

Used terms: [], a