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Proof step 5 from proof lls-one (previous step)

⊦ lls(r0, r1, a ' + []) = r0 => a × r1

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
⊦ lls(r, r1, a ' + x) = _∃(λ r0. r => a × r0 * lls(r0, r1, x))
Proof step 7:
⊦ _∃(λ r2. r0 => a × r2 * lls(r2, r1, [])) = r0 => a × r1

Rule argument

spec: <toplevel> name: lls-rec seq: ⊦ lls(r, r1, a ' + x) = _∃(λ r0. r => a × r0 * lls(r0, r1, x)) subst: [x, a, r1, r] → [[], a, r1, r0] flags: <all paths>

Additional information

Used terms: [], a, r1, r0