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Proof step 2 from proof alloc (previous step)

P(H) ⊦ ⟪choose r0 with ¬ r0 ∈ H ∧ r0 ≠ null in r := r0, H := H ++ r0⟫ ((r =>_ * P))(H)

Heuristic symbolic execution applied rule choose right

And obtained the following new goals

Rule argument

Additional information