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Proof step 3 from proof alloc (previous step)

P(H) ⊦ ⟪r := r0, H := H ++ r0⟫ ((r =>_ * P))(H), r0 = null, r0 ∈ H

Heuristic symbolic execution applied rule assign right

And closed the goal!

Rule argument

Additional information

Used simplifier rules: ¬ r ∈ H, r ≠ null ⊦ ((r =>_ * P))(H ++ r) ↔ P(H); (ss)%sep-ass: ⊦ (P0 * P1) * P2 = P0 * P1 * P2; from specification heap-sep%sep-com: ⊦ P0 * P1 = P1 * P0; from specification heap-sep