| rs2 ∩ rs1 = ∅, P(mk(rs2, f0)), r ∈ rs2, r ∈ rs2 → g0(r) = a, ∀ r. r ∈ rs2 → g0(r) = a, ∀ r. (g(r) = a ∧ r ∈ rs ↔ g0(r) = a ∧ r ∈ rs2 ∪ rs1) ∧ (g(r) = a ∧ r ∈ rs → f(r) = f0(r)) ⊦ # rs2 = 0, f0(r) = f(r), rs2 = ∅, P(mk(rs2, f)) |
rs2 ∩ rs1 = ∅, P(mk(rs2, f0)), r ∈ rs2, ∀ r0. r0 ∈ rs2 → g0(r0) = g0(r), ∀ r0. (g(r0) = g0(r) ∧ r0 ∈ rs ↔ g0(r0) = g0(r) ∧ r0 ∈ rs2 ∪ rs1) ∧ (g(r0) = g0(r) ∧ r0 ∈ rs → f(r0) = f0(r0)) ⊦ # rs2 = 0, f0(r) = f(r), rs2 = ∅, P(mk(rs2, f))