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Proof step 85 from proof rely-owned-unchgd (previous step)

rs2 ∩ rs1 = ∅, P(mk(rs2, f0)), r ∈ rs2, ∀ r0. r0 ∈ rs2 → g0(r0) = g0(r), ∀ r0. (g(r0) = g0(r) ∧ r0 ∈ rs ↔ g0(r0) = g0(r) ∧ r0 ∈ rs2 ∪ rs1) ∧ (g(r0) = g0(r) ∧ r0 ∈ rs → f(r0) = f0(r0)) ⊦ # rs2 = 0, f0(r) = f(r), rs2 = ∅, P(mk(rs2, f))

User applied rule all left

And closed the goal!

Rule argument

pos: left 5 terms: r abort: F discard: F computed: T

Additional information

Used simplifier rules: ⊦ r ∈ rs ∪ rs0 ↔ ¬(¬ r ∈ rs ∧ ¬ r ∈ rs0); (ss)%una: ⊦ (rs ∪ rs0) ∪ rs1 = rs ∪ rs0 ∪ rs1; from specification set-union[refset]%unc: ⊦ rs ∪ rs0 = rs0 ∪ rs; from specification set-union[refset] Used terms: r