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Proof step 2 from proof rely-transfer-owner (previous step)

⊦ a = a0, g(r) = a, rely(a, rs, f, g, rs, f, g(r; a0))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
r0 ∈ rs ⊦ # rs = 0, (r = r0 ⊃ a0;g(r0)) = a0, g(r0) = (r = r0 ⊃ a0;g(r0)), g(r) = (r = r0 ⊃ a0;g(r0)), rs = ∅

Rule argument

Additional information

Used simplifier rules: rely: ⊦ rely(a, rs0, f0, g0, rs1, f1, g1) ↔ (∀ r. (g0(r) = a ∧ r ∈ rs0 ↔ g1(r) = a ∧ r ∈ rs1) ∧ (g0(r) = a ∧ r ∈ rs0 → f0(r) = f1(r)));%size-zero-01: ⊦ rs ≠ ∅ → # rs ≠ 0; (forward) from specification set-basic[refset]%ne-01: ⊦ r ∈ rs → rs ≠ ∅; (forward) from specification set-basic[refset]