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Proof step 3 from proof rely-transfer-owner (previous step)

r0 ∈ rs ⊦ # rs = 0, (r = r0 ⊃ a0;g(r0)) = a0, g(r0) = (r = r0 ⊃ a0;g(r0)), g(r) = (r = r0 ⊃ a0;g(r0)), rs = ∅

User applied rule case distinction

And closed the goal!

Rule argument

pos: right 3

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