| P0(H1), P1(H0), H1 ⊥ H0, ∀ r. r ∈ H1 ∨ r ∈ H0 → O(r) = me ⊦ ((!(me, O, P0) * !(me, O, P1)))(H1 ∪ H0), P0(H1) ∧ (∀ r. r ∈ H1 → O(r) = me) |
P0(H1), P1(H0), r ∈ H1, H1 ⊥ H0, ∀ r. r ∈ H1 ∨ r ∈ H0 → O(r) = me ⊦ O(r) = me, ((!(me, O, P0) * !(me, O, P1)))(H1 ∪ H0)