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Proof step 24 from proof compact-local (previous step)

P0(H1), P1(H0), r ∈ H1, H1 ⊥ H0, ∀ r. r ∈ H1 ∨ r ∈ H0 → O(r) = me ⊦ O(r) = me, ((!(me, O, P0) * !(me, O, P1)))(H1 ∪ H0)

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 5 terms: r

Additional information

Used terms: r