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Theorem suffix-max-sum-step

n < # ar ⊦ 0 ≤ i ∧ 0 ≤ i + ar[n] ∧ maximum-suffix-sum(subarray(ar, 0, n), m, i) → maximum-suffix-sum(subarray(ar, 0, n + 1), m, i + ar[n])

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