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Proof step 8 from proof sorted-shift-one (previous step)

2 + m < # A, n < n0, n < # A, A[2 + m] < A[m], 2 + m < n0, m + 1 < n0, m + 1 < # A, n ≤ m, n0 ≤ # A, n ≤ m + 1, n ≤ m ∧ m + 1 < n0 → ¬ A[m + 1] < A[m], ∀ n1. n ≤ n1 ∧ n1 + 1 < n0 → ¬ A[n1 + 1] < A[n1] ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
m + 1 < # A, m + 1 < n0, 2 + m < n0, A[2 + m] < A[m], n < # A, n < n0, 2 + m < # A, n ≤ m + 1, n0 ≤ # A, n ≤ m, ∀ n1. n ≤ n1 ∧ n1 + 1 < n0 → ¬ A[n1 + 1] < A[n1] ⊦ A[m + 1] < A[m]

Proof step 8 from proof sorted-shift-one (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information