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Proof step 9 from proof sorted-shift-one (previous step)

m + 1 < # A, m + 1 < n0, 2 + m < n0, A[2 + m] < A[m], n < # A, n < n0, 2 + m < # A, n ≤ m + 1, n0 ≤ # A, n ≤ m, ∀ n1. n ≤ n1 ∧ n1 + 1 < n0 → ¬ A[n1 + 1] < A[n1] ⊦ A[m + 1] < A[m]

User applied rule all left

And closed the goal!

Rule argument

pos: left 11 terms: m + 1 abort: F discard: F computed: F

Additional information

Used simplifier rules: a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic%c: ⊦ m + n = n + m; from specification nat-basic%nll: ⊦ ¬ b < a ∧ b < c → a < c; (forward) from specification oelem%nnn: ⊦ ¬ c < b ∧ ¬ a < c → ¬ a < b; (forward) from specification oelem Used terms: m + 1