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Proof step 2 from proof initialization (previous step)

n ≠ 0 ⊦ ⟪tree_buffer_init#(n; ; h0, xs0)⟫ ⟨caterpillar_init#(n; ; h, xs, xs_len, ys)⟩ (prefixn(h, xs + ys) = prefixn(h, xs0) ∧ # xs + # ys ≤ # xs0 ∧ h0 = h)

Heuristic unfold applied rule call right

And obtained the following new goals

Proof step 3:
⊦ ⟪if n > 0 then h := n, xs := [] else abort⟫ ⟨caterpillar_init#(n; ; h1, xs1, xs_len, ys)⟩ (prefixn(h1, xs1 + ys) = prefixn(h1, xs) ∧ # xs1 + # ys ≤ # xs ∧ h = h1), n = 0

Rule argument

pos: right 1

Additional information

Used simplifier rules: tree_buffer_init#(n; ; h, xs){h := n, xs := []};