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Proof step 3 from proof initialization (previous step)

⊦ ⟪if n > 0 then h := n, xs := [] else abort⟫ ⟨caterpillar_init#(n; ; h1, xs1, xs_len, ys)⟩ (prefixn(h1, xs1 + ys) = prefixn(h1, xs) ∧ # xs1 + # ys ≤ # xs ∧ h = h1), n = 0

Heuristic symbolic execution applied rule if positive right

And obtained the following new goals

Proof step 4:
⊦ ⟪h := n, xs := []⟫ ⟨caterpillar_init#(n; ; h1, xs1, xs_len, ys)⟩ (prefixn(h1, xs1 + ys) = prefixn(h1, xs) ∧ # xs1 + # ys ≤ # xs ∧ h = h1), n = 0

Rule argument

Additional information

Used simplifier rules: ⊦ m > n ↔ n < m; (s)% ⊦ 0 < m ↔ m ≠ 0; (s)