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Proof step 23 from proof process-one (previous step)

((r => a0 × r0 * ls(r0, y) * del-list(rx0, n0) * P))(H) ⊦ r = null, r0 = null, ∃ x. # x ≤ n0 + # y ∧ (((ls(r0, x) * del-list(rx0, n0 + # y - # x)) * P))(H -- r)

User applied rule exists right

And obtained the following new goals

Proof step 24:
((r => a0 × r0 * ls(r0, y) * del-list(rx0, n0) * P))(H) ⊦ r = null, r0 = null, # y ≤ n0 + # y ∧ (((ls(r0, y) * del-list(rx0, n0 + # y - # y)) * P))(H -- r)

Rule argument

pos: right 3 terms: y abort: F discard: T computed: T

Additional information

Used terms: y