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Proof step 24 from proof process-one (previous step)

((r => a0 × r0 * ls(r0, y) * del-list(rx0, n0) * P))(H) ⊦ r = null, r0 = null, # y ≤ n0 + # y ∧ (((ls(r0, y) * del-list(rx0, n0 + # y - # y)) * P))(H -- r)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 25:
((r => a0 × r0 * ls(r0, y) * del-list(rx0, n0) * P))(H) ⊦ r = null, r0 = null, (((ls(r0, y) * del-list(rx0, n0)) * P))(H -- r)

Rule argument

Additional information

Used simplifier rules: ⊦ m + n - m = n; (s)%c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ m ≤ m + n; (s)