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Theorem k-Extension

⊦ st0 ≠ st1 ↔ ¬(∀ a. (a ∈ st0 ↔ a ∈ st1) ∧ (a ∈ st0 → st0[a] = st1[a]))

Type: A user defined theorem
Validity: The proof is valid.
Features:
Comment:
Used by: del-notin, rew,
Used by units in proved state:
Proof exists?: Yes

View the proof

Infos about the proof

Proved?: Yes
Interactions: 4
Proof steps: 8
Used lemmas: notmemlookup, Extension,
Used spec theorems:
- Used simplifier rules: