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Proof step 6 from proof cyclic-floyd-def (previous step)

m = 0, reachable-n(H, m, r, r0), reachable-n(H, m * n, r, r1), ∀ n0. reachable-n(H, m + n0 * n, r, r0) ⊦ n = 0, ∃ n, r0. n ≠ 0 ∧ reachable-n(H, n, r, r0) ∧ reachable-n(H, 2 * n, r, r0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
∀ n0. reachable-n(H, n0 * n, r0, r0) ⊦ n = 0, ∃ n, r1. n ≠ 0 ∧ reachable-n(H, n, r0, r1) ∧ reachable-n(H, 2 * n, r0, r1)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ m + n = n + m], [CSIMPSEQ : ⊦ (m + n0) + n1 = m + n0 + n1], [CSIMPSEQ : ⊦ 0 + m = m], [CSIMPSEQ : ⊦ m * n = n * m], [CSIMPSEQ : ⊦ m0 * m * n = (m0 * m) * n], [CSIMPSEQ : ⊦ m * 0 = 0], [CSIMPSEQ : ⊦ reachable-n(H, 0, r, r0) ↔ r = r0])]]