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Proof step 64 from proof cyclic-floyd-def (previous step)

∃ m, r0. reachable-n(H, m, r, r0) ∧ (∃ n. n ≠ 0 ∧ (∀ n0. reachable-n(H, m + n0 * n, r, r0))) ⊦ ∃ n, r0. n ≠ 0 ∧ reachable-n(H, n, r, r0) ∧ reachable-n(H, 2 * n, r, r0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 63:
reachable-n(H, m, r, r0), ∀ n0. reachable-n(H, m + n0 * n, r, r0) ⊦ n = 0, ∃ n, r0. n ≠ 0 ∧ reachable-n(H, n, r, r0) ∧ reachable-n(H, 2 * n, r, r0)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]