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Proof step 69 from proof cyclic-floyd-def (previous step)

∃ n, r0. n ≠ 0 ∧ reachable-n(H, n, r, r0) ∧ reachable-n(H, 2 * n, r, r0) ⊦ cyclic(r, H)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 68:
reachable-n(H, 2 * n, r, r0), reachable-n(H, n, r, r0) ⊦ n = 0, cyclic(r, H)

Rule argument

[emptyarg]

Additional information

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