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Proof step 71 from proof cyclic-floyd-def (conclusion)

⊦ cyclic(r, H) ↔ (∃ n, r0. n ≠ 0 ∧ reachable-n(H, n, r, r0) ∧ reachable-n(H, n + n, r, r0))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 70:
⊦ cyclic(r, H) ↔ (∃ n, r0. n ≠ 0 ∧ reachable-n(H, n, r, r0) ∧ reachable-n(H, 2 * n, r, r0))

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ m + n = n + m], [CSIMPSEQ : ⊦ (m + n0) + n1 = m + n0 + n1], [CSIMPSEQ : ⊦ m + m = 2 * m])]]