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Proof step 24 from proof cyclic-weak-def (previous step)

# H + 1 ≠ 0, ∃ x. path(x, H) ∧ hd x = r ∧ x .last = r0 ∧ # x = (# H + 1) + 1, ∀ n. ∃ r0. reachable-n(H, n, r, r0) ⊦ cyclic(r, H)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 23:
# x = 2 + # H, path(x, H), ∀ n. ∃ r0. reachable-n(H, n, hd x, r0) ⊦ cyclic(hd x, H)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ m + n = n + m], [CSIMPSEQ : ⊦ (m + n0) + n1 = m + n0 + n1], [CSIMPSEQ : ⊦ m + 1 ≠ 0])]]