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Proof step 2 from proof legal-nxt-1 (previous step)

∀ r. r ∈ H ∧ H[r] .nxt ≠ null → H[r] .nxt ∈ H, r ∈ H ⊦ H[r] .nxt = null, H[r] .nxt ∈ H

User applied rule all left

And closed the goal!

Rule argument

[EXRARG : pos: left 1, [extquanttermlist: (r)abort:F, discard:T, computed:F]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (r)]]