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Proof step 2 from proof legal-nxt-2 (conclusion)

⊦ legal(H) ∧ r ∈ H ∧ ¬ H[r] .nxt ∈ H → H[r] .nxt = null

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 1:
⊦ legal(H) ∧ r ∈ H ∧ H[r] .nxt ≠ null → (¬ H[r] .nxt ∈ H ↔ false)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]