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Proof step 15 from proof path-dups (previous step)

firstn(m, x1) ≠ [], (r ' + x1)[m] = r, path(r ' + x1, H), m ≤ # x1, ¬ path(r ' + firstn(m, x1), H) ∨ firstn(m, x1) .last ≠ r ⊦ x1 = [], m = 0, reachable-n(H, m, r, r)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 14:
(r ' + x1)[m] = r, path(r ' + x1, H), m ≤ # x1, ¬ path(firstn(m, x1) .last ' + firstn(m, x1), H) ∨ firstn(m, x1) .last ≠ r ⊦ x1 = [], m = 0, reachable-n(H, m, r, r)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ firstn(n, x0) = [] ↔ n = 0])]]