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Proof step 76 from proof path-dups (previous step)

∃ m, n. m < # x ∧ n < # x ∧ m ≠ n ∧ x[m] = x[n], path(x, H) ⊦ cyclic(hd x, H)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 75:
x[m] = x[n], path(x, H), n < # x, m < # x ⊦ m = n, x = [], cyclic(hd x, H)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ # x0 = 0 ↔ x0 = []], [CSIMPFORWARD : ⊦ m < n → n ≠ 0])]]