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Proof step 8 from proof path-nodups-subset (previous step)

path(r ' + x0, H), # H ≤ # x0 ⊦ ∃ H0. # H0 < # x0 ∧ path(x0, H0), dups(x0), r ∈ x0

User applied rule exists right

And obtained the following new goals

Proof step 7:
path(r ' + x0, H), # H ≤ # x0 ⊦ # (H -- r) < # x0 ∧ path(x0, H -- r), dups(x0), r ∈ x0

Rule argument

[EXRARG : pos: right 1, [extquanttermlist: (H -- r)abort:F, discard:T, computed:F]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (H -- r)]]